Stacking kill %'s

Rokenn · 02-06-2002, 10:48 AM

If I have a projectile that gives A 2% kill chance and a weapon that gives 6% how do they stack? Is it a 2% check followed by a 6%? or one check at 8%? Also does crit strike stack the same way?

Loredweller · 02-06-2002, 12:14 PM

AFIK, they're probabilities. 2% means only that in 100 throws there should be 2 positive events. In fact even that is not completely true - three is some high enough probability you'd get positive outcome in 2% of throws. In case of infinite number of throws that probability becomes 1 (or 100%). In case you mentioned there is 6% for possibility the weapon launches fatal arrow without any importance of missile's features. Arrow's fatality should be determined at the moment it hit the target without counting what weapon has launched it. So there might be both lucky, one of them or none - and only if the target is even hit. In result the probability the shoot getting the mark might be lethal is more than 6%, altogether it definitely is less than 8% - both multiplied by your hit ratio.
Of course, so it is by theory. I know nothing about how programmers have implemented it in code. If they allowed overflow of, say, resistences (as it has been mentioned here), it makes me uneasy and lets me worry if programmers even have heard about mathematics nowadays.

[ 02-06-2002: Message edited by: Loredweller ]

02-06-2002, 10:48 AM	#1
Rokenn Galvatron Join Date: January 22, 2002 Location: california wine country Age: 60 Posts: 2,193	If I have a projectile that gives A 2% kill chance and a weapon that gives 6% how do they stack? Is it a 2% check followed by a 6%? or one check at 8%? Also does crit strike stack the same way? __________________ “This is an impressive crowd, the haves and the have mores. <br />Some people call you the elite. <br />I call you my base.”<br />~ George W. Bush (2000)

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02-06-2002, 12:14 PM	#2
Loredweller Elite Waterdeep Guard Join Date: January 8, 2002 Location: Latvia Posts: 17	AFIK, they're probabilities. 2% means only that in 100 throws there should be 2 positive events. In fact even that is not completely true - three is some high enough probability you'd get positive outcome in 2% of throws. In case of infinite number of throws that probability becomes 1 (or 100%). In case you mentioned there is 6% for possibility the weapon launches fatal arrow without any importance of missile's features. Arrow's fatality should be determined at the moment it hit the target without counting what weapon has launched it. So there might be both lucky, one of them or none - and only if the target is even hit. In result the probability the shoot getting the mark might be lethal is more than 6%, altogether it definitely is less than 8% - both multiplied by your hit ratio. Of course, so it is by theory. I know nothing about how programmers have implemented it in code. If they allowed overflow of, say, resistences (as it has been mentioned here), it makes me uneasy and lets me worry if programmers even have heard about mathematics nowadays. [ 02-06-2002: Message edited by: Loredweller ]

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