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Old 09-15-2002, 09:02 AM   #1
Neb
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Okay, I need a bit of help with some homework. Maths homework to be precise. What I need help with is:

Polynomic Division
Border Values
and Asymptotes

My first problem is with PD.

(X^4+4X^3-4X-1)/(X-1) and (X^4+4X^3-4X-1)/(X+1) What effect will the difference between dividing with (X-1) and (X+1) have?
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Old 09-15-2002, 10:08 AM   #2
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Ah old maths. I COULD do it for you, but I won't because you won't learn anything. Do your own Homework! [img]tongue.gif[/img]
 
Old 09-15-2002, 10:51 AM   #3
Neb
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I don't want anyone to do it for me. Just to help me do it so I can bloody understand the damn junk.
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Old 09-15-2002, 10:57 AM   #4
andrewas
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Quote:
Originally posted by Neb:
I don't want anyone to do it for me. Just to help me do it so I can bloody understand the damn junk.
Its a simple long division. But its a long time since ive done it and every time I try this one I hit th x^-1 term which isnt common at pre-university level. In fact it never happened to me at uni either, so I suspect im making a mistake.

EDIT - and as soon as I post this, I see that Ive got the last term down wrong.

Which part are you stuck on anyway?

[ 09-15-2002, 10:59 AM: Message edited by: andrewas ]
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Old 09-15-2002, 01:10 PM   #5
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Old 09-15-2002, 02:11 PM   #6
Kaltia
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Old 09-15-2002, 04:50 PM   #7
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Quote:
Originally posted by Neb:
Okay, I need a bit of help with some homework. Maths homework to be precise. What I need help with is:

(X^4+4X^3-4X-1)/(X-1) and (X^4+4X^3-4X-1)/(X+1) What effect will the difference between dividing with (X-1) and (X+1) have?
Just remember that variables represent numbers. For example: what is the differnece between 176 div 2 = 88 and 176 div 4 = 44? This is the case if you let x=3.

Just use long div and work the problem. Don't forget the 0x^2 term.
Here's a start for you ... how many x terms can you factor out of x^4? .... x^3.

Hope it helps .... good luck!
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Old 09-15-2002, 11:01 PM   #8
Gabrielles blades
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I think i know the what to do on that:
What effect will the difference between dividing with (X-1) and (X+1) have?
this means ignore the top part of the equation
X-1 in the denominator for any eqn will: create a 0 at 1 which means the equation cannot work since you cannot divide by zero (atleast not till you get to calculus) So it will have a "hole" at 1 and will function normally for the rest of eternity. this means its range? or was it domain is (-infinity, 1) to (1, infinity) *please note that i cant remember if ( means include the end number or exclude it i think its either ( or [ but i digress
So for the X+1 it has a hole at -1 and is fine for the rest of eternity and so its thing should look something like this (-infinity, -1) (-1, infinity)

Also note that i ummm forgot most math and that all of this is probably wrong in some way or other, but the basics are down i think.
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Old 09-15-2002, 11:04 PM   #9
Gabrielles blades
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Oh
almost forgot
the only time u cannot ignore the top is if it has a X+1 or X-1 in it (youll have to factor the equation to see if it does); if it does then u can just divide the thing out.
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Old 09-15-2002, 11:17 PM   #10
Firestormalpha
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OUCH, what kind of math is this again? Algebra? Algebra 2? Calculus? Don't say Trig. because then I'd have to shoot you for being smarter than me. I'm only taking integrated ( its above algbra 2 but below Trig and Calc.) Anyways I probably used to know how to do that, but I'm trying to finish highschool this year. Thus much of my previous knowledge takes a vacation.
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