Maths Revision

[Aragorn1]

Wow, that's a bit tough! In my case it was 'meh, you'll probably get an A'. God knows what ot would have been if they went on my maths test scores. Good for uni applications! THen again, i've done the ASs, so that would give them a better indication.

[Gangrell]

Originally posted by Azred: Seraph, your girlfriend got the right answer and differentiated the function correctly. Then function is question is an exponential function; in its generic form looks like this: f(x) = k ^ x, with k being a non-negative numbers (usually). The first derivative takes the form f'(x) = (ln k) * (k ^ x). Multiple derivatives have this form: (f(n))(x) = ((ln k)^n) * (k ^ x). If it helps, you could always think of letting k = e, because finding derivatvies for e^x is really easy. [img]graemlins/beigesmilewinkgrin.gif[/img] Interestingly, if you let k = sqrt(2), begin with an x-value of 1, and iterate the function (the x-value of the next step is the f(x)-value from the last step) then the iterated function values converge to sqrt(2). [img]graemlins/petard.gif[/img]

I hate you all now [img]tongue.gif[/img]