Where have I gone wrong?

Nanobyte · 01-18-2004, 08:37 PM

I think this might be the last one. I've scanned all my remaining problems, and I feel I can do them. The problem includes:

Determine the value for c on [2,5] that satisfies the Mean Value Theorem (f'(c)= ^f(b)-f(a)/_b-a) for f(x)=x²-3/x-1.

And here's all the work I've included:

f(5)= 5²-3/5-1
= ^25-3/₄
= ²²/₄= ¹¹/₂

f(2)= 2²-3/2-1
= ^4-3/₁
= 1

f(x)= (x²-3)(x-1)^-1
f'(x)= 2x(x-1)^-1-(x²-3)(x-1)
= (2-2x)-(x²-3)(x-1)
= -2(-1+x)-(x²-3)(x-1)
= (x+1)(-2-x²+3)
= (x+1)(-x²+1)

(c+1)(-c²+1)= ^9/2/₃
c+1= ³/₂ -c²+1= ³/₂
c= ¹/₂ c= ...

The answer is supposed to be 3, but I'm not getting that. Can anyone point out my error?

[ 01-18-2004, 09:28 PM: Message edited by: Nanobyte ]

Donut · 01-19-2004, 07:07 AM

I think the answer is ''green'

Bozos of Bones · 01-19-2004, 07:22 AM

Yes, but the amount of Pokemon included in the left side of the equation doens't come close to a monkey with glasses. Sorry, but I think he'd be better off answering "chicken curry".

Vaskez · 01-19-2004, 08:12 AM

I think you messed up the differentiation....
it should be 2x(x-1)^-1 - (x^2-3)(x-1)^-2 (you missed off the power of -2)
then carry on from there, solve by partial fractions I think.

Dragonshadow · 01-19-2004, 08:27 AM

You have to think about the mathimatical equvelent of a squid, times by pi with a monkey milk, then divide by a squid head, the number of eyes on a blind spider and then you get...
Eggs.

Cloudbringer · 01-19-2004, 08:52 AM

LOL! Nanobyte, I think you may go off the deep end if you include green squids and Pokemons in there! Vaskie seems to have helped out, though!

Nanobyte · 01-19-2004, 09:41 AM

Quote:

Originally posted by Cloudbringer:
LOL! Nanobyte, I think you may go off the deep end if you include green squids and Pokemons in there! Vaskie seems to have helped out, though!

I guess a few laughs never hurt anybody. [img]smile.gif[/img] Thanks Vaskez, for pointing out my mistake.

Sythe · 01-19-2004, 10:45 AM

LOL Dragonshadow! Is this college level math or something? This is way out of my leauge.

Dragonshadow · 01-19-2004, 10:59 AM

Quote:

Originally posted by Sythe:
LOL Dragonshadow! Is this college level math or something? This is way out of my leauge.

Yes...no....maybe....
BTW Nanobyte, you aren't a mathsteacher or a lawyer,are you?

Nanobyte · 01-19-2004, 11:13 AM

It's AP (Advanced Placement), which is considered college level.

edited: and no, I'm neither. I actually plan on becoming a game designer, and even then, will most likely lean towards writing than programming.

[ 01-19-2004, 11:16 AM: Message edited by: Nanobyte ]

01-19-2004, 07:07 AM	#2
Donut Jack Burton Join Date: March 1, 2001 Location: Airstrip One Age: 40 Posts: 5,571	I think the answer is ''green' __________________ [img]\"http://www.wheatsheaf.freeserve.co.uk/roastspurs.gif\" alt=\" - \" /> <br />Proud member of the Axis of Upheaval<br />Official Titterer of the Laughing Hyenas<br />Josiah Bartlet - the best President the US never had.<br />The 1st D in the D & D Show

01-19-2004, 07:22 AM	#3
Bozos of Bones Apophis Join Date: July 29, 2003 Location: The Underdark cavern of Zagreb Age: 37 Posts: 4,679	Yes, but the amount of Pokemon included in the left side of the equation doens't come close to a monkey with glasses. Sorry, but I think he'd be better off answering "chicken curry". __________________ MAKE LOVE, NOT SPAM!

01-19-2004, 08:12 AM	#4
Vaskez Takhisis Follower Join Date: April 30, 2001 Location: szép Magyarország (well not right now) Posts: 5,089	I think you messed up the differentiation.... it should be 2x(x-1)^-1 - (x^2-3)(x-1)^-2 (you missed off the power of -2) then carry on from there, solve by partial fractions I think. __________________ Too set in his ways to ever relate If he could set that aside, there'd be heaven to pay But weathered and aged, time swept him to grave Love conquers all? Damn, I'd say that area's gray

01-19-2004, 08:52 AM	#6
Cloudbringer Ironworks Moderator Join Date: March 1, 2001 Location: Upstate NY USA Posts: 19,737	LOL! Nanobyte, I think you may go off the deep end if you include green squids and Pokemons in there! Vaskie seems to have helped out, though! __________________ "Don't take life for granted." Animal (may he rest in peace)

01-19-2004, 10:45 AM	#8
Sythe Ra Join Date: May 19, 2002 Location: The US of A Age: 35 Posts: 2,365	LOL Dragonshadow! Is this college level math or something? This is way out of my leauge. __________________ Slythe is back! Back again! Haha! <br /><br />[url]\"http://imageshack.us\" target=\"_blank\"> [img]\"http://img472.imageshack.us/img472/9928/130blood4ts.jpg\" alt=\" - \" /></a>

01-18-2004, 08:37 PM	#1
Nanobyte Thoth - Egyptian God of Wisdom Join Date: March 1, 2001 Location: NC Age: 38 Posts: 2,890	I think this might be the last one. I've scanned all my remaining problems, and I feel I can do them. The problem includes: Determine the value for c on [2,5] that satisfies the Mean Value Theorem (f'(c)= ^f(b)-f(a)/_b-a) for f(x)=x²-3/x-1. And here's all the work I've included: f(5)= 5²-3/5-1 = ^25-3/₄ = ²²/₄= ¹¹/₂ f(2)= 2²-3/2-1 = ^4-3/₁ = 1 f(x)= (x²-3)(x-1)^-1 f'(x)= 2x(x-1)^-1-(x²-3)(x-1) = (2-2x)-(x²-3)(x-1) = -2(-1+x)-(x²-3)(x-1) = (x+1)(-2-x²+3) = (x+1)(-x²+1) (c+1)(-c²+1)= ^9/2/₃ c+1= ³/₂ -c²+1= ³/₂ c= ¹/₂ c= ... The answer is supposed to be 3, but I'm not getting that. Can anyone point out my error? [ 01-18-2004, 09:28 PM: Message edited by: Nanobyte ]

01-19-2004, 08:27 AM	#5
Dragonshadow Quth-Maren Join Date: February 17, 2003 Location: Portsmouth Age: 34 Posts: 4,145	You have to think about the mathimatical equvelent of a squid, times by pi with a monkey milk, then divide by a squid head, the number of eyes on a blind spider and then you get... Eggs.

01-19-2004, 11:13 AM	#10
Nanobyte Thoth - Egyptian God of Wisdom Join Date: March 1, 2001 Location: NC Age: 38 Posts: 2,890	It's AP (Advanced Placement), which is considered college level. edited: and no, I'm neither. I actually plan on becoming a game designer, and even then, will most likely lean towards writing than programming. [ 01-19-2004, 11:16 AM: Message edited by: Nanobyte ]

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