Just use Concentration(M) = moles/volume (in litres);
750ml of a 0.5M solution contains 0.375moles (0.750 x 0.5)
The solution of acid is 16 Molar, and vol.= moles/conc.;
So the volume of 16M HNO3 solution containing 0.375moles is 0.0234 Litres (23.4mL) (0.375 divided by 16)
You can converts the number of moles used into mass, but this just adds in a couple of extra steps that aren't needed in this case.
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