Ironworks Gaming Forum - View Single Post - Chemistry help: solutions, concentrations, and molarity

Nanobyte · 11-23-2002, 02:00 PM

I can't understand how to solve this problem:
How many milliliters of 16.0 M HNO3 would be required to prepare 750. mL of a 0.500 M solution?

It says to see Sample Problem 13-3, but it includes grams into the equation, when all I have is the volume and concentration. Can someone help me w/ this problem?

Alright, I think I have it.
Would you take .5Mx.75L= .38mol/16M= .02L
.38mol/.02L= 19M.. hmm, that isn't right.

.5Mx750mL= 375mol/16M= 23.44mL
375mol/23.44mL= 16M.. but, the molarity equation says that you have to do the process in L..

Darn it.

[ 11-23-2002, 02:16 PM: Message edited by: Nanobyte ]

11-23-2002, 02:00 PM	#1
Nanobyte Thoth - Egyptian God of Wisdom Join Date: March 1, 2001 Location: NC Posts: 2,890	I can't understand how to solve this problem: How many milliliters of 16.0 M HNO3 would be required to prepare 750. mL of a 0.500 M solution? It says to see Sample Problem 13-3, but it includes grams into the equation, when all I have is the volume and concentration. Can someone help me w/ this problem? Alright, I think I have it. Would you take .5Mx.75L= .38mol/16M= .02L .38mol/.02L= 19M.. hmm, that isn't right. .5Mx750mL= 375mol/16M= 23.44mL 375mol/23.44mL= 16M.. but, the molarity equation says that you have to do the process in L.. Darn it. [ 11-23-2002, 02:16 PM: Message edited by: Nanobyte ]