Ah so you're Dracorion at Pandemonium? Didn't realise. I've answered this over at Pande but I'm so kind, I'll paste it here
6x^2 + 6x -12 = (3x - 3)(2x + 4) = 0
so the 2 roots are 3x = 3 so x = 1 and 2x = -4 so x = -2
You can easily check if you've done the factorisation right by multiplying out the brackets and you should get back to what you started. You can check that your x values are correct by putting them in 1 at a time and seeing if you get 0 as you expect. If you put x = 1 in then you get (3(1) - 3)(2x+4) =
0(2x+4) = 0 so you know x=1 is definitely a root. Do the same for the other value.
In the 2nd one you don't actually have to do any calculation, you can see by inspection that x = 0 and x = 1 are roots because substituting either of those into the equation gives you a value of 0.
[ 11-10-2002, 04:50 PM: Message edited by: Vaskez ]