Quote:
Originally posted by Neb:
quote:
Originally posted by Sazerac:
quote:
Originally posted by Neb:
Hm, alright, it's just that we haven't worked that much with ln and are in the middle of working with log.
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Oh! Well, you can do it with log, too...just substitute it for ln in Azred's formula. It all cancels out, regardless of what base you use. [img]smile.gif[/img]
Cheers,
-Saz[/QUOTE]Goody! Now how much more maths can I convince you guys to do for me? 
1) log(x+1) + log(x-1) = 0
2) log((x^2)-1) - log(x+1)-1 = 0[/QUOTE]On logs, when adding them, you multiply their arguments. Like: Log A + log B = Log AB. When subtracting logs, you divide their arguments. Like: Log A - Log B = Log (A/B).
So for your first one: log(x+1) + log(x-1) = log((x+1)(x-1) or log(x^2 - 1). Set that equal to zero, take the antilog of both sides, and solve for X.
(I'd do it for you, but A) you need to learn to do it yourself, and B) some yayhoo deleted the Windows calculator off this computer, the swine! [img]graemlins/1pissed.gif[/img] ) Ah well...hope that helps!
-Saz