Quote:
Originally posted by Callum:
Y = 10(0.84^X),
But then it asks for a function for this new graph... And as far as I know... there is no way to draw a graph that suddenly jumps up 10 before continuing as normal. Is there? So the function is the same, except every six hours, it increases by 10...
Is there a way to obtain a function for this?
|
Yes. It needs to be done piecewise, so that for every six hours you have a new graph. But finding this graph is surprisingly easy:
1. Find the function value of Y at the time the dose of 10 is administered. (NOT AFTER it has been administered but BEFORE)
2. Add this value to the dose you added, being 10.
3. Assuming the drop rate is the same (it should be unvariable under the taken dose) you take new formula: Y' = (10 + value before new dose) (0.84^x)
4. For the next jump of six hours, repeat, only this time you will most likely find a different value when administering new dose.