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MxM = swipe
MxF = bite
FXF = bite
21 swipe 34 bite
now, it says all attack each other once, you simply need to find out for the males what numbers are multiples of 21
ie 1, 3, 7, 21
so its either 10 M or 22 M
(y1) + 21(y2) + (y1)(y2) = 34
now y2 cant be greater than 1 for this one, so
y1 + 21 + y1 = 34
2(y1) = 13
so y1 = 13/2 which is an impossible number for this question (cant have halves...)
Ok, so we know that it has to be 10 males, so how many females?
3(y1) + 7(y2) + (y1)(y2) = 34
i forget how to solve this type of problem (so good old plugging and chugging worked...) and you get that y1 = 4 and y2 = 2 to make that equation true or a total of 6 F
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