Quote:
Originally posted by Night Stalker:
based on you first post
f(x)=| e^2 for all x less than the natural log of 2
OR
| 2 for all x greater than or equal too ln(2).
f(x) is one of two constants.
|
I understand this. But under the circumstances, I have to prove one of those answers to be true.
Quote:
based of the second post:
f(x)=|e^x ...... this is a variable function until x>= ln(2), then f(x) = 2
The other stuff you posted is just to show that the inverse function of ln(x) = e^x thats all don't confuse these concepts.
There are two types of inverses. Multiplicitave and Additive.
For multiplicative, x times its inverse = 1
For additive, x plus it's inverse = 0
For example 2 x 1/2 = 1
2 + (-2) = 0
|
I don't get what you're saying, Night Stalker. If I solve ln2, it comes out to be .6931471806. If I plug this number into my e
x, I get out 2. That is what I meant in my previous post.
[ 01-17-2004, 04:06 PM: Message edited by: Nanobyte ]