Yeah, I got it again. I did the calculations at school once ( math -analyses ), but the holidays diminished my intelligence to a level where I couldnt figure it out anymore.
Though I'd like to know what the diameter of a champagne bottle is, and the diameter of its neck. As the above calculations require the bottle to be a square with the coins touching the sides at convenient points.
I'm assuming that what you do to know the proportions of the "big square" that draws around all the traingular-placed coins is move each side of the "little square" a radius to the left,right, up and down ( the left side to the left, right side to the right etc. ). This would make the "Little square" match the "big square" ( which is the smallest possible sqaure to house all 3 coins ).
The only drawbacks this has is:
1. The big square has an extra 4 spots of aire in the square's corners that werent there in the calculations of the small square.
2. Both sqaures arent truly squares, as the width is indeed 1 coin for the small and 2 coins for the big square, but the lenght isnt 1, respectively 2 coins. They are squares if you use your method, but in reality the "top-coin" would slide into the gap that the 2 "base-coins" have because of their curvature.
Did I get that right ( I doubt it since the whole holiday_not_intelligent_enough_anymore is still true ) ?
[ 08-19-2003, 08:20 AM: Message edited by: daan ]