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-   -   HELP!!!! *physics* (http://www.ironworksforum.com/forum/showthread.php?t=71288)

Kaz 10-21-2001 02:40 PM

I am writing a Physics test on Thursday, and am kind of stuck on this point.
We are doing (among others) high voltage cables and why we use them. Now, I have a question. The resistance of the cables would be Resistance = rho * length/area (R=rho * l/A), rho being the resistance factor of the material. Now, you also calculate the resistance by Resistance = Voltage/Amperage (R = U/I). However, of course, if you change the voltage the resistance of the cables would change, but that is impossible because they are a fixed length, area and material! HELP!!! What changes? What IS the resistance I got in the second computation?

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Ronn_Bman 10-21-2001 02:47 PM

Quote:

Originally posted by Kaz:
What IS the resistance I got in the second computation?


That would be the resistance of my thick skull, and your trying to run this question through it http://www.ironworksforum.com/ubb/no...es/biggrin.gif


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Arvon 10-21-2001 02:48 PM

It's been a few thousand years since I had to deal with this, but if you change voltage the current changes.

Byronas 10-21-2001 02:52 PM

I wish you good luck since I can't help you.
I'm in the second class of high school you knowhttp://www.ironworksforum.com/ubb/no...es/biggrin.gifhttp://www.ironworksforum.com/ubb/no...es/biggrin.gifhttp://www.ironworksforum.com/ubb/no...es/biggrin.gif!

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Kaz 10-21-2001 03:00 PM

I'm in 10th - when does High School start in Greece? I hope I didn't mess the whole thing up - I had to translate all the technical terms from German into English, I may have gotten some wrong.

Byronas 10-21-2001 03:02 PM

A man starts high school in Greece after 6 years in primary school.

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Neb 10-21-2001 03:03 PM

Ack! Not physics! I'm allergic to that! Save meeeeee! I'm meeeeeeeeeltiiiiing!

Kaz 10-21-2001 03:15 PM

Quote:

Originally posted by Neb:
Ack! Not physics! I'm allergic to that! Save meeeeee! I'm meeeeeeeeeltiiiiing!
I DID say *physics* in the title, if you read it it's your own fault. http://www.ironworksforum.com/ubb/no...miles/nono.gif http://www.ironworksforum.com/ubb/no...miles/wink.gif *fetches bucket* Here, melt into that.

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Mirac Honorguard 10-21-2001 03:26 PM

Quote:

Originally posted by Arvon:
It's been a few thousand years since I had to deal with this, but if you change voltage the current changes.
Yes, Kaz, what Avron says here is true, the resistance of the wires are always the same the U/I = R is just a way to calculate the value of the resistance if you don't have any other information. so shortly put, R (resistance) is always the same, if the voltage (U) changes it only affects the current (I) and if the current (I) changes, the voltage (U) is likely to change.
Hope this helps, if you have more physics questions, just shoot, I'm in this business


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Kaz 10-21-2001 03:39 PM

Hm... but if I have both U and I and they do not add up to the R I got by rho*length/Area? To be more exact, something like this

R = rho * l/A
R = U/I
rho = 0.017
l= 100km
A = 0.8 cm2
U = 150kV
I = 533.33 A
Therefore
R = rho * l/A
R = 0.017 Ohm per whatever * 100km/0.8cm
R = 212500 Ohm

HOWEVER
R = U/I
R = 150000V/533.33A
R = 281.25 Ohm

WHAT THE HECK? THE RESISTANCE CAN'T BE 212500 Ohm AND 281.25 Ohm AT THE SAME TIME!!!! *sob*



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mistral4543 10-21-2001 04:41 PM

Kaz - Sorry that I can't help much... the only thing I noticed is that unit length in the numerator and denominator of the first formula (R = rho * l/A) is inconsistent. Ie, the area should be converted into square metres since you've changed the length from km to m.

Gee, sorry I'm not much help... let's hope Mirac returns soon to help you out with this. http://www.ironworksforum.com/ubb/no...iles/frown.gif

Kaz 10-21-2001 04:46 PM

Quote:

Originally posted by mistral4543:
Kaz - Sorry that I can't help much... the only thing I noticed is that unit length in the numerator and denominator of the first formula (R = rho * l/A) is inconsistent. Ie, the area should be converted into square metres since you've changed the length from km to m.

Gee, sorry I'm not much help... let's hope Mirac returns soon to help you out with this. http://www.ironworksforum.com/ubb/no...iles/frown.gif

I did, I just skipped that step. What I noticed was that I'm not exactly sure what unit rho is measured in...

Avatar 10-21-2001 05:04 PM

Kaz:

I'm doing Electronic Engineering at Cambridge 1st year:

R changes ONLY with material, temperature, length and area.

I think http://www.ironworksforum.com/ubb/no...miles/wink.gif I ought to know...

Voltage (potential difference) is adjustable and the current THROUGH the resistor changes acoordingly. THE REISITOR can heat up as a result of this...

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Rikard 10-22-2001 01:30 AM

Quote:

Originally posted by Kaz:
I am writing a Physics test on Thursday, and am kind of stuck on this point.
We are doing (among others) high voltage cables and why we use them. Now, I have a question. The resistance of the cables would be Resistance = rho * length/area (R=rho * l/A), rho being the resistance factor of the material. Now, you also calculate the resistance by Resistance = Voltage/Amperage (R = U/I). However, of course, if you change the voltage the resistance of the cables would change, but that is impossible because they are a fixed length, area and material! HELP!!! What changes? What IS the resistance I got in the second computation?


Whoohooo Physics http://www.ironworksforum.com/ubb/no...miles/wink.gif
Don;t you have Chemestry Questions?
I love thise http://www.ironworksforum.com/ubb/no...miles/wink.gif

oh wait the question right...
Well Kazzy Honey
It's quite easy
If you higher the voltage and the resistance stays the same
What happens?
The Amperage highers aswell (the current through the resistor as Avatar calles it)

Simple in'it
so basicly U/I=l/A (i'm sure that th area ain't A but have no idea what it IS)




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Mirac Honorguard 10-22-2001 09:42 AM

Quote:

Originally posted by Avatar:
Kaz:

I'm doing Electronic Engineering at Cambridge 1st year:

R changes ONLY with material, temperature, length and area.

I think http://www.ironworksforum.com/ubb/no...miles/wink.gif I ought to know...

Voltage (potential difference) is adjustable and the current THROUGH the resistor changes acoordingly. THE REISITOR can heat up as a result of this...


Hello fellow Electronic Engineer (I supposed to do second year, but I delayed for a half year).
Anyways, Rikard, that is NOT right what you've said about U/I = l/A. Kaz, forget that, not right!!
About your problem with the calculations, I did the calculation as well, this is how it should be :

rho = 0.017
l = 100 km = 100.000 m
A = 0.8 cm2 = 0.008 dm2 = 0.00008 m2
R = rho * l/A
R = 0.017 * (100.000/0.00008) = 21250000 ohm

This is totally different from the formula U/I = R !!!!!

I'll give a an example, try to solve this one :

What is R (using R = rho * l/A ) when
A = 10 dm2
l = 30 m
rho = 0.5
R =????

Solve R

With the R you calculated here
you go on with this question (using U/I=R is equal (if rewritten) to R*I =U ) :

U = ?????
I = 5000 mA
R = what you calculated in the first question.

I'll check in later this day, if you still can't solve it email me.
Hope this helps

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[This message has been edited by Mirac Honorguard (edited 10-22-2001).]

DragonMage 10-22-2001 09:46 AM

Quote:

Originally posted by Mirac Honorguard:
Hello fellow Electronic Engineer (I supposed to do second year, but I delayed for a half year).
Anyways, Rikard, that is NOT right what you've said about U/I = l/A. Kaz, forget that, not right!!
About your problem with the calculations, I did the calculation as well, this is how it should be :

rho = 0.017
l = 100 km = 100.000 m
A = 0.8 cm2 = 0.008 dm2 = 0.00008 m2
R = rho * l/A
R = 0.017 * (100.000/0.00008) = 21250000 ohm

This is totally different from the formula U/I = R !!!!!

I'll give a an example, try to solve this one :

What is R (using R = rho * l/A ) when
A = 10 dm2
l = 30 m
rho = 0.5
R =????

Solve R

With the R you calculated here
you go on with this question (using U/I=R is equal (if rewritten) to R*I =U ) :

U = ?????
I = 5000 mA
R = what you calculator in the first question.

I'll check in later this day, if you still can't solve it email me.
Hope this helps

O....M....G....Beam me back down, Scotty. There IS intelligent life down there! http://www.ironworksforum.com/ubb/no...miles/wink.gif Haven't seen the likes of this in years! Still hurts my head! http://www.ironworksforum.com/ubb/no...miles/wink.gif

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Avatar 10-22-2001 10:07 AM

Quote:

Originally posted by DragonMage:
O....M....G....Beam me back down, Scotty. There IS intelligent life down there! http://www.ironworksforum.com/ubb/no...miles/wink.gif Haven't seen the likes of this in years! Still hurts my head! http://www.ironworksforum.com/ubb/no...miles/wink.gif



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Harkoliar 10-22-2001 10:16 AM

AAAAAAAARRRRRRGGGGGG... physics, must run.. and hide.. and... groan... http://www.ironworksforum.com/ubb/no...iles/smile.gif

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DragonMage 10-22-2001 10:40 AM

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Well, I hope you didn't think I was implying that no one else posting here was intelligent. http://www.ironworksforum.com/ubb/no...les/tongue.gif Mirac's post just brought back terrifying memories of Electrical Engineering classes an old b/f of mine was taking, gee, 15 years ago. I would help him with the homework sometimes. *ouch, my brain*

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Hopeless Romantic *sigh*

Kaz 10-22-2001 10:50 AM

I think I can think again today - so if R(cable) = rho * l/A; then R = U/I would be the resistance of the ENTIRE circuit (or whatever it's called in English). Right?
Also got my other physics thing sorted out, with a little help from the teacher. Logical, actually.

Rikard 10-22-2001 11:46 AM



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[This message has been edited by Rikard (edited 10-22-2001).]


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